Motor

• Shear stress
  • Stress = F (force)/ A (cross section area)
    • Finding F
      • Total load on the rear wheel = 350 * (2/ 3) * 9.8 = 2286 N
      • F= 2286 / 6, F = 380 N
    • Finding A
      • A = 0.01(disk thickness) * 0.005 (minimum distance between the 1cm hole and the aluminum disk edge)
      • = 0.00005 m